Lecture 16

04/13/2023, Th.

Today

1. Multiband expansion for Ωab

We use the fact

(1)λan|H|n=δnnEnλa=an|nEn+Enn|an+n|Hλa|n

If nn,

(2)n|Hλa|n=(EnEn)n|a|n

Then

(3)Ωab=AbλaAaλb=i[an|bnbn|an]=inn[an|nn|bnbn|nn|an]

Finally we have

(4)Ωab=innn|aH|nn|bH|n(ab)(EnEn)2

 

2. A-B phase a Berry phase

Aharonov-Bohm's phase us a quantum mechanical phenomenon, where a charged particle can pick up a phase in its wavefunction, although it is confined to a region where magnetic field is zero. This is so because even though in the region where the charged particle travels B=0, the vector potential a(r) is not.

This can be derived heuristically in a semiclassical approximation of the path integral, which says the transition is characterized by the phase of the classical path. The amplitude is

(5)eiS[Γ]/

where S is the action. With the magnetic field or vector potential

(6)S=0tdtL(r˙,r)

with

(7)L=L0ear˙.

So there is a magnetic change of phase

(8)Δϕ=eΓdra(r)

Consider the electron goes from 1 to 2 via Γ and Γ. The phase difference between these two events are then given by

(9)e(Γ+Γ)adr=eΦ=2πΦΦ0

which cannot be gauged away, since Φ is gauge invariant (规范不变的)

AB

We now illustrate how this phase can be formulated in terms of a Berry phase. We suppose the charged particle is an electron confined in a box (a confining potential), and is moved along with the box around the magnetic flux.

(10)H=12m(p+ea)2+V(rR) confining potential

Without magnetic field, a=0 everywhere. The ground state at each point R is |ψ0(R).

Now turn on the B-field. We make sure that the location where the box travels has B=0. The presence of the vector potential amounts to a gauge transformation

(11)|ψ(R)=exp(ieRra(r)dr)|ψ0(R)

Because ×a=0 inside the box, the line integral is path independent so along as it is in the box.

(12)H|ψ(R)=exp[ieRra(r)dr](p22m+V(rR))|ψ0(R)=exp[ieRra(r)dr]E|ψ0(R)=E|ψ(R)

The Berry connection

(13)ψ(R)|iR|ψ(R)=ψ0(R)|iR|ψ0(R)ea(R)

The Berry phase

(14)γ=eCadR+iΣ(ψ0Rαψ0Rβαβ)=0 because ψ0(rR) is real.dσ

Then we see that A-B phase is just the Berry phase.

 

3. Two-level system

The Hamiltonian of a two-level system can be written as

(15)H=hσ=hxσx+hyσy+hzσz=[hzhxihyhx+ihyhz]

We can write the vector h in spherical coordinates

(16)h=(hx,hy,hz)=h(sinθcosϕ,sinθsinϕ,cosθ),h>0.

Then there are two branches, ε±=±h. Let's focus on the lower branch

(17)|ψ=[eiϕsinθ2cosθ2]

Let's compute the Berry connection

(18)Aθ=ψ|iθ|ψ=0Aϕ=ψ|iϕ|ψ=sin2θ2

So the Berry curvature is

(19)Ωθϕ=12sinθ.

If we keep h constant, and change (θ,ϕ), we can make the particle move on the surface of a sphere. If the trajectory is closed, Σ, then the Berry phase is

(20)γ=ΣdθdϕΩθϕ=12Σsinθdθdϕ=12× solid angle subtended by Σ.

So if Σ is the entire surface, then γ=2π. On the other hand

(21)γ=ΣAdl=0

because Σ=. This is apparently in contradiction with the Stokes theorem.

sph di

The contradiction arises from the the fact that Aθ,Aϕ cannot be continuous and single-valued at the same time. For the gauge choice we have, Aϕ(π)=1. This means there is a singularity at the south pole, no matter the h value. This kind of singularity is called the Dirac string.

This is analogous to the Dirac's magnetic monopole, if we switch to the Cartesian coordinates

(22)Ωab=Ωθϕ(θ,ϕ)(ha,hb)=12(ϕ,cosθ)(ha,hb)

we find

(23)Ω=h2h3

which is singular at the origin.

image-20230412220359199

 

4. Geometric properties of Bloch bands

For a single electron in a periodic potential, Bloch theorem says its eigenstates are irreducible representation of lattice translation

(24)H|ψnk=εnk|ψnk

where the Bloch function has the following property

(25)ψnk(r+R)=eikRψnk(r)ψnk(r)=eikrunk(r).

We call |unk the cell-periodic part of |ψnk.

We can now make the following transformation

(26)Hk=eikrHeikr

which we will call the Bloch Hamiltonian. Then we have the following Schrodinger equation

(27)Hk|unk=εnk|unk.

We then define the Berry connection (again) of Bloch bands

(28)Amn(k)=umk|ik|unk

Note that by our normalization convention, |umk are unit-cell normalized, so the above bra-ket signifies integral within one unit cell.

For this course, we will focus on usually problems involving a single band. The one-band (Abelian) Berry connection is

(29)An(k)=umk|ik|unk

with which we can introduce the Berry curvature (again, Abelian)

(30)Ωn(k)=k×An(k)

Let's now place the system in a uniform electric field

(31)E=a˙

The crystal Hamiltonian is

(32)H=(p+ea)22m+V

And the Bloch Hamiltonian

(33)Hk=(p+ea+k)22m+V(r)

but we may just define a new wavevector that depends on time

(34)q(t)=k+ea

which admits the same eigenstates with time-dependent q vectors

(35)Hq(t)|unq(t)=εnq(t)|unq(t).

So

(36)q˙=eE

Now consider the first-order wavefunction

(37)|unk(1)=|unkinn|unkunk|t|unkεnkεnk

The velocity operator

(38)r˙k=i[Hk,r]=Hkk

So the velocity to the first order of perturbation

(39)vnk=vnk(0)innunk|r˙k|unkunk|t|unkc.c.εnkεnk

where the first term is the group velocity of the nth Bloch band, and the second term is the anomalous velocity (we will see how it reduces to the anomalous velocity in the anomalous Hall effect shortly).

We note the following: for nn

(40)0=kun|Hk|un=(εnεn)kun|un+un|kHk|un

we find that

(41)vnk=vnk(0)nnkunk|unkunk|it|unkc.c.=vnk(0)i(unkk|unktc.c.)

So we have

(42)vnka=vnk(0)aΩkat

where Ωkat is the anomalous velocity in a direction

(43)Ωkat=i(unkka|unktunkt|unkka)

So combining with the expression for q˙ in electric field, and writing now q as k

(44)vnka=vnk(0)aΩkakbk˙b=vnk(0)a(k˙×Ω)a

which is the same as what we have obtained from semiclassical dynamics.